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Question
Physics
A 120 volt AC source is connected across a pure inductor of inductance 0.70 henry. If the frequency of the source is 60 Hz, the current passing through the inductor is
Q. A
120
volt AC source is connected across a pure inductor of inductance
0.70
henry. If the frequency of the source is
60
Hz
, the current passing through the inductor is
2376
246
Alternating Current
Report Error
A
4.55 A
B
0.355 A
C
0.455 A
D
3.55 A
Solution:
Z
=
X
L
=
2
π
×
60
×
0.7
∴
i
=
Z
120
=
2
π
×
60
×
0.7
120
=
0.455
A
.