A 10 V battery with internal resistance 1 Ω and a 15 V battery with internal resistance 0.6 Ω are connected in parallel to a voltmeter (see figure). The reading in the voltmeter will be close to :

Question

A 10 V battery with internal resistance 1 Ω and a 15 V battery with internal resistance 0.6 Ω are connected in parallel to a voltmeter (see figure). The reading in the voltmeter will be close to : (A) 11.9 V (B) 12.5 V (C) 13.1 V (D) 24.5 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/90cf6fb76b9e722b87107ea8105c5001-.png" /> i=(15-10/1.6)=(50/16) (V) reads 15-i(0.6)=15-((50/16) × (3/5))=15-(15/8)=15 × (7/8)=13.1 V

Q. A $10 V$ battery with internal resistance $1 Ω$ and a $15 V$ battery with internal resistance $0.6 Ω$ are connected in parallel to a voltmeter (see figure). The reading in the voltmeter will be close to :

11.9 V

12.5 V

13.1 V

24.5 V

$i = \frac{15 - 10}{1.6} = \frac{50}{16}$
(V) reads $15 - i (0.6) = 15 - (\frac{50}{16} \times \frac{3}{5}) = 15 - \frac{15}{8} = 15 \times \frac{7}{8} = 13.1 V$

Q. A 10V battery with internal resistance 1Ω and a 15V battery with internal resistance 0.6Ω are connected in parallel to a voltmeter (see figure). The reading in the voltmeter will be close to :