A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then the current flowing through the bulb is

Question

A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then the current flowing through the bulb is (A) (5/11) A  (B) (1/2) A  (C)  2 A  (D) (3/4) A

Tardigrade Admin · Accepted Answer

I = (P/V) = (100/220) = (5/11) A

Q. A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then the current flowing through the bulb is

$\frac{5}{11} A$

$\frac{1}{2} A$

$2 A$

$\frac{3}{4} A$

$I = \frac{P}{V} = \frac{100}{220}$
$= \frac{5}{11} A$

Q. A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then the current flowing through the bulb is

115​A

21​A

2A

43​A

I=VP​=220100​ =115​A

$\frac{5}{11} A$

$\frac{1}{2} A$

$2 A$

$\frac{3}{4} A$

$I = \frac{P}{V} = \frac{100}{220}$
$= \frac{5}{11} A$