A 100 Ω resistance and a capacitor of 100 Ω reactance are connected in series across a 220 V source. When the capacitor is 50 % charged, the peak value of the displacement current is

Question

A 100 Ω resistance and a capacitor of 100 Ω reactance are connected in series across a 220 V source. When the capacitor is 50 % charged, the peak value of the displacement current is (A) 2.2 A (B) 11 A (C) 4.4 A (D) 11 √2 A

Tardigrade Admin · Accepted Answer

Xc = 100 R = 100 Z = √(100)2 + (100)2 = 100 √2 I = (E/Z) = (220/100√2) = (2.2/√2) I0 = √2 I = (2.2/√2) ×√2 = 2.2 A

Q. A $100 Ω$ resistance and a capacitor of $100 Ω$ reactance are connected in series across a $220 V$ source. When the capacitor is $50%$ charged, the peak value of the displacement current is

2.2 A

11 A

4.4 A

$112 A$

$X_{c} = 100$
$R = 100$
$Z = (100)^{2} + (100)^{2} = 1002$
$I = \frac{E}{Z} = \frac{220}{100 2} = \frac{2.2}{2}$
$I_{0} = 2 I = \frac{2.2}{2} \times 2 = 2.2 A$

Q. A 100Ω resistance and a capacitor of 100Ω reactance are connected in series across a 220V source. When the capacitor is 50% charged, the peak value of the displacement current is