A 100 m long wire having cross-sectional area 6.25 × 10-4 m 2 and Young's modulus is 1010 Nm -2 is subjected to a load of 250 N, then the elongation in the wire will be:

Question

A 100 m long wire having cross-sectional area 6.25 × 10-4 m 2 and Young's modulus is 1010 Nm -2 is subjected to a load of 250 N, then the elongation in the wire will be: (A) 6.25 × 10-3 m (B) 4 × 10-3 m (C) 4 × 10-4 m (D) 6.25 × 10-6 m

Tardigrade Admin · Accepted Answer

Elongation in wire δ=( F ℓ/ AY ) δ=(250 × 100/6.25 × 10-4 × 1010) δ=4 × 10-3 m

Q. A $100 m$ long wire having cross-sectional area $6.25 \times 1 0^{- 4} m^{2}$ and Young's modulus is $1 0^{10} N m^{- 2}$ is subjected to a load of $250 N$ , then the elongation in the wire will be:

$6.25 \times 1 0^{- 3} m$

$4 \times 1 0^{- 3} m$

$4 \times 1 0^{- 4} m$

$6.25 \times 1 0^{- 6} m$

Elongation in wire $δ = \frac{F ℓ}{A Y}$
$δ = \frac{250 \times 100}{6.25 \times 1 0 ^{- 4} \times 1 0 ^{10}}$
$δ = 4 \times 1 0^{- 3} m$

Q. A 100m long wire having cross-sectional area 6.25×10−4m2 and Young's modulus is 1010Nm−2 is subjected to a load of 250N, then the elongation in the wire will be:

6.25×10−3m

4×10−3m

4×10−4m

6.25×10−6m