A 10 μ F capacitor is charged to a potential difference of 1000 V. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6 μ F capacitor. What is the final potential difference across each capacitor?

Question

A 10 μ F capacitor is charged to a potential difference of 1000 V. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6 μ F capacitor. What is the final potential difference across each capacitor? (A) 167 V (B) 100 V (C) 625 V (D) 250 V

Tardigrade Admin · Accepted Answer

The capacitance of system of capacitors

C = C_{1} + C_{2}

= 10 + 6 = 16 μ F

The charge stored in first capacitor

q = C_{1} V

= 10 \times 1000 = 1 0^{4} μ C

Final potential difference across each capacitor

V^{'} = q / C = 1 0^{4} /16

= 625

volt

Q. A $10 μ F$ capacitor is charged to a potential difference of $1000 V$ . The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged $6 μ F$ capacitor. What is the final potential difference across each capacitor?

167 V

100 V

625 V

250 V

750 V

The capacitance of system of capacitors
$C = C_{1} + C_{2}$
$= 10 + 6 = 16 μ F$
The charge stored in first capacitor
$q = C_{1} V$
$= 10 \times 1000 = 1 0^{4} μ C$
Final potential difference across each capacitor
$V^{'} = q / C = 1 0^{4} /16$
$= 625$ volt

Q. A 10μF capacitor is charged to a potential difference of 1000V. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6μF capacitor. What is the final potential difference across each capacitor?