A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 ms-1, at right angles to the horizontal component of the earth's magnetic field, of 0.3 × 10-4 Wb/m2. The value of the induced emf in wire is :

Question

A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 ms-1, at right angles to the horizontal component of the earth's magnetic field, of 0.3 × 10-4 Wb/m2. The value of the induced emf in wire is : (A) 2.5 × 10-3 V (B) 1.1 × 10-3V (C) 0.3 × 10-3 V (D) 1.5 × 10-3 V

Tardigrade Admin · Accepted Answer

Induced emf = Bv ℓ sin 45 = 0.3 × 10-4 × 5 × 10 × (1/√2) = 1.1 × 10-3 V

Q. A $10 m$ long horizontal wire extends from North East to South West. It is falling with a speed of $5.0 m s^{- 1}$ , at right angles to the horizontal component of the earth's magnetic field, of $0.3 \times 1 0^{- 4} Wb / m^{2}$ . The value of the induced emf in wire is :

$2.5 \times 1 0^{- 3} V$

$1.1 \times 1 0^{- 3} V$

$0.3 \times 1 0^{- 3} V$

$1.5 \times 1 0^{- 3} V$

Induced emf $= B v ℓ sin 45$
$= 0.3 \times 1 0^{- 4} \times 5 \times 10 \times \frac{1}{2}$
= $1.1 \times 1 0^{- 3} V$

Q. A 10m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0ms−1, at right angles to the horizontal component of the earth's magnetic field, of 0.3×10−4Wb/m2. The value of the induced emf in wire is :

2.5×10−3V

1.1×10−3V

0.3×10−3V

1.5×10−3V