Q.
A 10kg metal block is attached to a spring of spring constant 1000nm−1. A block is displaced from equilibrium position by 10cm and released. The maximum acceleration of the block is
We know that spring does SHM
So, the restoring force is proportional to displacement
i.e., F=−mω2y...(i) F=−ky...(ii)
where k= force constant of the spring m=10kg A=10cm=0.1m
Comparing the both equation, we get ω2=mk ⇒ω=mk=101000 =10rad/s
and acceleration in SHM amax=−ω2⋅y
where ω2 is constant =−102×(0.1)=−10m/s2=10ms−2