A 10 g bullet moving at 200 m / s stops after penetrating 5 cm of wooden plank. The average force exerted on the bullet will be

Question

A 10 g bullet moving at 200 m / s stops after penetrating 5 cm of wooden plank. The average force exerted on the bullet will be (A) 2000 N (B) -2000 N (C) 4000 N (D) -4000 N

Tardigrade Admin · Accepted Answer

m=10 g, u=200 m / s, s=5 cm final velocity v=0 Using v2=u2+2 as a=(u2/2 s) and for force F=-m a (retarding force)

Q. A $10 g$ bullet moving at $200 m / s$ stops after penetrating $5 c m$ of wooden plank. The average force exerted on the bullet will be

2000 N

-2000 N

4000 N

-4000 N

$m = 10 g, u = 200 m / s, s = 5 c m$
final velocity $v = 0$
Using $v^{2} = u^{2} + 2$ as
$a = \frac{u ^{2}}{2 s}$
and for force $F = - ma$ (retarding force)

Q. A 10g bullet moving at 200m/s stops after penetrating 5cm of wooden plank. The average force exerted on the bullet will be