A 1 kg block 'B' rests as shown on a bracket 'A' of same mass. Constant forces F1=20 N and F2=8 N start to act at time t=0 when the distance of block B from pulley is 50 cm. Time (in sec) when block B reaches the pulley is t. Find the value of 10 t.

Question

A 1 kg block 'B' rests as shown on a bracket 'A' of same mass. Constant forces F1=20 N and F2=8 N start to act at time t=0 when the distance of block B from pulley is 50 cm. Time (in sec) when block B reaches the pulley is t. Find the value of 10 t. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-gpfbbmrcf9krk62v.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

First find out acceleration of A so for this ⇒ a=20-2F2=20-2× 8 aA=4 m / s2 Now use pseudo concept (in which A is non inertial frame) Solution

⇒ 8-4=4 m / s2 Now (50/100)=(1/2)× 4× t2 t=(1/2)=0.5 sec ⇒ 10t=5

Q. A 1kg block 'B' rests as shown on a bracket 'A' of same mass. Constant forces F1​=20N and F2​=8N start to act at time t=0 when the distance of block B from pulley is 50cm. Time (in sec) when block B reaches the pulley is t. Find the value of 10t.

First find out acceleration of A so for this ⇒a=20−2F2​=20−2×8 aA​=4m/s2 Now use pseudo concept (in which A is non inertial frame) ⇒8−4=4m/s2 Now 10050​=21​×4×t2 t=21​=0.5sec ⇒10t=5

Q. A $1 k g$ block ' $B$ ' rests as shown on a bracket ' $A$ ' of same mass. Constant forces $F_{1} = 20 N$ and $F_{2} = 8 N$ start to act at time $t = 0$ when the distance of block $B$ from pulley is $50 c m$ . Time (in sec) when block $B$ reaches the pulley is $t$ . Find the value of $10 t$ .