A 0.5 kg block of brass (density =8 × 103 kg ⋅ m -3 ) is suspended from a string. What is the tension in the string if the block is completely immersed in water ? (g=10 m ⋅ s-2)

Question

A 0.5 kg block of brass (density =8 × 103 kg ⋅ m -3 ) is suspended from a string. What is the tension in the string if the block is completely immersed in water ? (g=10 m ⋅ s-2) (A) 5 N (B) (0.5/8 × 103) N (C) (5/8) N (D) (35/8) N

Tardigrade Admin · Accepted Answer

Mass of block, m=0.5 kg Density, ρ=8 × 103 kgm -3 Volume of block, V=(m/ρ)=(0.5/8 × 103) =6.25 × 10-5 m 3 When block is fully immersed in water, then upthrust force on the block F1=m g=V ⋅ ρw × g =6.25 × 10-5 × 103 × 10 =0.625 N ∴ Tension in the string T=m g-F1 (upthrust force) =0.5 × 10-0.625=4.375 N =(35/8) N

Q. A $0.5 k g$ block of brass (density $= 8 \times 1 0^{3} k g \cdot m^{- 3}$ ) is suspended from a string. What is the tension in the string if the block is completely immersed in water ? $(g = 10 m \cdot s^{- 2})$

$5 N$

$\frac{0.5}{8 \times 1 0 ^{3}} N$

$\frac{5}{8} N$

$\frac{35}{8} N$

Q. A 0.5kg block of brass (density =8×103kg⋅m−3 ) is suspended from a string. What is the tension in the string if the block is completely immersed in water ? (g=10m⋅s−2)

5N

8×1030.5​N

85​N

835​N

Q. A $0.5 k g$ block of brass (density $= 8 \times 1 0^{3} k g \cdot m^{- 3}$ ) is suspended from a string. What is the tension in the string if the block is completely immersed in water ? $(g = 10 m \cdot s^{- 2})$

$5 N$

$\frac{0.5}{8 \times 1 0 ^{3}} N$

$\frac{5}{8} N$

$\frac{35}{8} N$