85 g CaCO 3 (limestone sample), on heating produces exactly the same amount of CO 2 which converts 30 g of MgO to MgCO 3. The percentage purity of limestone sample is

Question

85 g CaCO 3 (limestone sample), on heating produces exactly the same amount of CO 2 which converts 30 g of MgO to MgCO 3. The percentage purity of limestone sample is (A) 80 % (B) 82.4 % (C) 88.24 %  (D) 84.8 %

Tardigrade Admin · Accepted Answer

underset40 gMgO+ underset44 gCO2 → MgCO3 40 g MgO needs CO 2=44 g 30 g Mg O needs CO 2=(44 × 30/40)=33 g underset100 gCaCO3 → CaO+ underset44 gCO2 44 g CO 2 is obtained from CaCO 3=100 g 33 g CO 2 is obtained from CaCO 3 =(100 × 33/44)=75 g Percentage purity of CaCO 3 sample =(75/85) × 100=88.24 %

Q. $85 g C a C O_{3}$ (limestone sample), on heating produces exactly the same amount of $C O_{2}$ which converts $30 g$ of $M g O$ to $M g C O_{3}$ . The percentage purity of limestone sample is

$80%$

$82.4%$

$88.24%$

$84.8%$

Q. 85gCaCO3​ (limestone sample), on heating produces exactly the same amount of CO2​ which converts 30g of MgO to MgCO3​. The percentage purity of limestone sample is

80%

82.4%

88.24%

84.8%

40gMgO​+44gCO2​​→MgCO3​ 40gMgO needs CO2​=44g 30gMgO needs CO2​=4044×30​=33g 100gCaCO3​​→CaO+44gCO2​​ 44gCO2​ is obtained from CaCO3​=100g 33gCO2​ is obtained from CaCO3​ =44100×33​=75g Percentage purity of CaCO3​ sample =8575​×100=88.24%

Q. $85 g C a C O_{3}$ (limestone sample), on heating produces exactly the same amount of $C O_{2}$ which converts $30 g$ of $M g O$ to $M g C O_{3}$ . The percentage purity of limestone sample is

$80%$

$82.4%$

$88.24%$

$84.8%$