Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
(7C0 + 7C1) + (7C2 + 7C3) + .... + (7C6 + 7C7) =
Q.
(
7
C
0
+
7
C
1
)
+
(
7
C
2
+
7
C
3
)
+
....
+
(
7
C
6
+
7
C
7
)
=
1920
222
KEAM
KEAM 2018
Report Error
A
2
8
−
2
50%
B
2
7
−
1
0%
C
2
7
33%
D
2
8
−
1
17%
E
2
7
−
2
17%
Solution:
(
7
C
0
+
7
C
1
)
+
(
7
C
2
+
7
C
3
)
+
...
+
(
7
C
6
+
7
C
7
)
=
7
C
0
+
7
C
1
+
…
+
7
C
7
=
2
7
[
∵
C
0
+
C
1
+
C
2
+
...
+
C
n
=
2
n
]