60 g of a compound on analysis produced 24 g carbon, 4 g hydrogen and 32 g oxygen. The empirical formula of the compound is

Question

60 g of a compound on analysis produced 24 g carbon, 4 g hydrogen and 32 g oxygen. The empirical formula of the compound is (A) CH2O2 (B) CH2O (C) CH4O (D) C2H4O2

Tardigrade Admin · Accepted Answer

C: H: O = (24/12): (4/1): (32/16) = 2: 4: 2 or 1: 2: 1 ∴ Empirical formula = CH2O

Q. 60 g of a compound on analysis produced 24 g carbon, 4 g hydrogen and 32 g oxygen. The empirical formula of the compound is

$C H_{2} O_{2}$

$C H_{2} O$

$C H_{4} O$

$C_{2} H_{4} O_{2}$

C : H : O = $\frac{24}{12} : \frac{4}{1} : \frac{32}{16} = 2 : 4 : 2$
or 1 : 2 : 1
$∴$ Empirical formula = $C H_{2} O$

Q. 60 g of a compound on analysis produced 24 g carbon, 4 g hydrogen and 32 g oxygen. The empirical formula of the compound is

CH2​O2​

CH2​O

CH4​O

C2​H4​O2​

C : H : O = 1224​:14​:1632​=2:4:2 or 1 : 2 : 1 ∴ Empirical formula = CH2​O

$C H_{2} O_{2}$

$C H_{2} O$

$C H_{4} O$

$C_{2} H_{4} O_{2}$

C : H : O = $\frac{24}{12} : \frac{4}{1} : \frac{32}{16} = 2 : 4 : 2$
or 1 : 2 : 1
$∴$ Empirical formula = $C H_{2} O$