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  4. 60 g of a compound on analysis produced 24 g carbon, 4 g hydrogen and 32 g oxygen. The empirical formula of the compound is

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Q. 60 g of a compound on analysis produced 24 g carbon, 4 g hydrogen and 32 g oxygen. The empirical formula of the compound is

Some Basic Concepts of Chemistry

Solution:

C : H : O = $\frac{24}{12} : \frac{4}{1} : \frac{32}{16} = 2 : 4 : 2$
or 1 : 2 : 1
$\therefore $ Empirical formula = $CH_2O$