6 boys 6 girls sit in a row at random. The probability that all the girls sit together is

Question

6 boys 6 girls sit in a row at random. The probability that all the girls sit together is (A) (1/432) (B) (12/431) (C) (1/132) (D) None of these

Tardigrade Admin · Accepted Answer

6 boys and 6 girls sit in a row in 12! ways. Number of ways when all six girls sit together = 7! × 6! ∴ Required probability = ( 7! × 6!/12!) = (1/132)

Q. $6$ boys & $6$ girls sit in a row at random. The probability that all the girls sit together is

$\frac{1}{432}$

$\frac{12}{431}$

$\frac{1}{132}$

$N o n e o f t h ese$

6 boys and 6 girls sit in a row in $12!$ ways. Number of ways when all six girls sit together = $7! \times 6!$
$∴$ Required probability = $\frac{7 ! \times 6 !}{12 !} = \frac{1}{132}$

Q. 6 boys & 6 girls sit in a row at random. The probability that all the girls sit together is

4321​

43112​

1321​

Noneofthese