Question

6.3 g of an acid is neutralized by 500 cc of 0.2 N NaOH solution. The equivalent mass of acid is

• A. 63
• B. 36
• C. 60
• D. 43

Answer 1

Answer: (A)

For neutralization, no. of gram equivalents of acid should be equal to no. of gram equivalents of base.
No. of gram equivalents of NaOH
$=\frac{500\times 0.2}{1000}=0.1$
Now, $\frac{w}{eq.massofacid}=0.1$
eq. mass of acid = $\frac{w}{0.1}=\frac{6.3}{0.1}=63$