6.025 × 1020 molecules of acetic acid are present in 500 ml of its solution. The concentration of solution is

Question

6.025 × 1020 molecules of acetic acid are present in 500 ml of its solution. The concentration of solution is (A) 0.002 M (B) 10.2 M (C) 0.012 M (D) 0.001 M

Tardigrade Admin · Accepted Answer

Moles of oxalic acid =(6.022 × 1020/6.022 × 1023)=10-3 moles Molarity =(10-3/500) × 1000 =2 × 10-3 M =0.002 M

Q. $6.025 \times 1 0^{20}$ molecules of acetic acid are present in $500 m l$ of its solution. The concentration of solution is

0.002 M

10.2 M

0.012 M

0.001 M

Moles of oxalic acid $= \frac{6.022 \times 1 0 ^{20}}{6.022 \times 1 0 ^{23}} = 1 0^{- 3}$ moles
Molarity $= \frac{1 0 ^{- 3}}{500} \times 1000$
$= 2 \times 1 0^{- 3} M = 0.002 M$

Q. 6.025×1020 molecules of acetic acid are present in 500ml of its solution. The concentration of solution is