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  4. 6.025 × 1020 molecules of acetic acid are present in 500 ml of its solution. The concentration of solution is

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Q. $6.025 \times 10^{20}$ molecules of acetic acid are present in $500\, ml$ of its solution. The concentration of solution is

Some Basic Concepts of Chemistry

Solution:

Moles of oxalic acid $=\frac{6.022 \times 10^{20}}{6.022 \times 10^{23}}=10^{-3}$ moles
Molarity $=\frac{10^{-3}}{500} \times 1000$
$=2 \times 10^{-3} M =0.002\, M$