Question

$6.02\times 10^{22}$ atoms of A, 0.2 mole of B and $12.04\times 10^{22}$ atoms of C combine to make a compound, the empirical formula of the compound is

• A. $A_2{B}_{2}C$
• B. $AB{C}_2$
• C. $A{B}_2{C}_2$
• D. $A_{2}BC$

Answer 1

Answer: (C)

Correct answer is (c) $A{B}_2{C}_2$