56 g of nitrogen and 8 g of hydrogen gas are heated in a closed vessel. At equilibrium 34 g of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively :

Question

56 g of nitrogen and 8 g of hydrogen gas are heated in a closed vessel. At equilibrium 34 g of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively : (A) 1 ,1, 2 (B) 2, 1, 2 (C) 1, 2, 2 (D) 2, 2, 1

Tardigrade Admin · Accepted Answer

beginarraylccc N 2 + 3 H 2 arrow 2 NH 3 2 4 & 0 2- x 4-3 x & 2 x endarray According to the question, 2 x =2 ⇒ x =1 Hence at equilibrium, number of moles of N 2=2- x =2-1=1 number of moles of H 2=4-3 x =4-3=1 number of moles of NH 3=2 x =2

Q. 56g of nitrogen and 8g of hydrogen gas are heated in a closed vessel. At equilibrium 34g of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively :

1 ,1, 2

2, 1, 2

1, 2, 2

2, 2, 1

\begin{array}{lccc} N _{2} & + & 3 H _{2} & \rightarrow & 2 NH _{3} \\ 2 & 4 & & 0 \\ 2- x & 4-3 x & & 2 x \end{array} According to the question, 2x=2⇒x=1 Hence at equilibrium, number of moles of N2​=2−x=2−1=1 number of moles of H2​=4−3x=4−3=1 number of moles of NH3​=2x=2

Q. $56 g$ of nitrogen and $8 g$ of hydrogen gas are heated in a closed vessel. At equilibrium $34 g$ of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively :