500 ml each of 2 × 10-2 M NaHSO 4 and 2 × 10-2 M Na 2 SO 4 are mixed. Calculate [ H +]in final solution. [Given: K a 2( H 2 S O 4)=10-2, √2=1.414 ] [Write your answer by multiplying with 105 ]

Question

500 ml each of 2 × 10-2 M NaHSO 4 and 2 × 10-2 M Na 2 SO 4 are mixed. Calculate [ H +]in final solution. [Given: K a 2( H 2 S O 4)=10-2, √2=1.414 ] [Write your answer by multiplying with 105 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

underset(0.01-x) HSO 4- leftharpoons underset(x)H ++ underset(0.01 + x) SO 4 2- 10-4-10-2 x=10-2 x+x2 x=(-2 × 10-2 ± √4 × 10-4+4 × 10-4/2) =(-2 × 10-2+2 × 10-2 × √2/2) =10-2+√2 10-2=0.414 × 10-2

Q. 500ml each of 2×10−2MNaHSO4​ and 2×10−2M Na2​SO4​ are mixed. Calculate [H+]in final solution. [Given: Ka2​(H2​SO4​)​=10−2,2​=1.414 ] [Write your answer by multiplying with 105 ]

(0.01−x)HSO4−​​⇌(x)H+​+(0.01+x)SO4​2−​ 10−4−10−2x=10−2x+x2 x=2−2×10−2±4×10−4+4×10−4​​ =2−2×10−2+2×10−2×2​​ =10−2+2​10−2=0.414×10−2

Q. $500 m l$ each of $2 \times 1 0^{- 2} M N a H S O_{4}$ and $2 \times 1 0^{- 2} M$ $N a_{2} S O_{4}$ are mixed. Calculate $[H^{+}]$ in final solution. [Given: $K_{a_{2} (H_{2} S O_{4})} = 1 0^{- 2}, 2 = 1.414$ ]
[Write your answer by multiplying with $1 0^{5}$ ]