500 g impure sample of textCaCO text3 on heating gives text70 textg of textCaO text. Percentage impurities in sample is

Question

500 g impure sample of textCaCO text3 on heating gives text70 textg of textCaO text. Percentage impurities in sample is (A) 25% (B) 50% (C) 75% (D) 80%

Tardigrade Admin · Accepted Answer

CaCO3 arrow CaO+CO2 Let the % purity is textx Mol: (500 × X/100 × 100) mol (500 × X/100 × 100)× 56=70 X=25 % Impurities =100-25=75 %

Q. $500 g$ impure sample of $CaCO_{3}$ on heating gives $70 g$ of $CaO .$ Percentage impurities in sample is

25%

50%

75%

80%

$C a C O_{3} \to C a O + C O_{2}$

Let the % purity is $x$
Mol: $\frac{500 \times X}{100 \times 100}$ mol

$\frac{500 \times X}{100 \times 100} \times 56 = 70$

$X = 25$

% Impurities $= 100 - 25 = 75%$

Q. 500g impure sample of CaCO3​ on heating gives 70g of CaO. Percentage impurities in sample is

25%

50%

75%

80%

CaCO3​→CaO+CO2​ Let the % purity is x Mol: 100×100500×X​ mol 100×100500×X​×56=70 X=25 % Impurities =100−25=75%

Q. $500 g$ impure sample of $CaCO_{3}$ on heating gives $70 g$ of $CaO .$ Percentage impurities in sample is

$C a C O_{3} \to C a O + C O_{2}$

Let the % purity is $x$
Mol: $\frac{500 \times X}{100 \times 100}$ mol

$\frac{500 \times X}{100 \times 100} \times 56 = 70$

$X = 25$

% Impurities $= 100 - 25 = 75%$