In the given reaction, all the HCl will be neutralized and NH4Cl will be formed and equivalent amount of NH4OH will remain in the solution. Thus, the final solution will contain NH4OH and NH4Cl, which can act as basic buffer solution. The concentration of NH4Cl and NH4OH will be same. pOH=pKb+log10[ Base ][ Salt ] pOH=4.75+log1011 pOH=4.75 pH=14−pOH =14−4.75=9.25