5 g of zinc is treated separately with an excess of (a) dilute hydrochloric acid and (b) aqueous sodium hydroxide. The ratio of the volumes of H2 evolved in these two reactions is :

Question

5 g of zinc is treated separately with an excess of (a) dilute hydrochloric acid and (b) aqueous sodium hydroxide. The ratio of the volumes of H2 evolved in these two reactions is : (A) 1: 2 (B) 1: 4 (C) 1: 1 (D) 2: 1

Tardigrade Admin · Accepted Answer

Zn+2HCl → ZnCl2+H2 Zn+2NaOH → Na2 ZnO2+H2 The ratio of the volume of H2 is 1: 1

Q. 5 g of zinc is treated separately with an excess of
(a) dilute hydrochloric acid and
(b) aqueous sodium hydroxide.
The ratio of the volumes of $H_{2}$ evolved in these two reactions is :

$1 : 2$

$1 : 4$

$1 : 1$

$2 : 1$

$Z n + 2 H Cl \to Z n C l_{2} + H_{2}$
$Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$
The ratio of the volume of $H_{2}$ is 1 : 1

Q. 5 g of zinc is treated separately with an excess of (a) dilute hydrochloric acid and (b) aqueous sodium hydroxide. The ratio of the volumes of H2​ evolved in these two reactions is :

1:2

1:4

1:1

2:1