5 boys and 3 girls sit in a line so that p is the number of arrangements when no two girls sit together and q is the number of arrangements when all the girls sit together, then (p/q) is

Question

5 boys and 3 girls sit in a line so that p is the number of arrangements when no two girls sit together and q is the number of arrangements when all the girls sit together, then (p/q) is (A) (10/3) (B) 20 (C) (5/9) (D) none of these

Tardigrade Admin · Accepted Answer

p=5 ! 6 C 3 ⋅ 3 !, q =6 ! ⋅ 3 ! ⇒ ( p / q )=(10/3)

Q. 5 boys and 3 girls sit in a line so that $p$ is the number of arrangements when no two girls sit together and $q$ is the number of arrangements when all the girls sit together, then $\frac{p}{q}$ is

$\frac{10}{3}$

20

$\frac{5}{9}$

none of these

$p = 5!^{6} C_{3} \cdot 3!, q = 6! \cdot 3!$
$\Rightarrow \frac{p}{q} = \frac{10}{3}$

Q. 5 boys and 3 girls sit in a line so that p is the number of arrangements when no two girls sit together and q is the number of arrangements when all the girls sit together, then qp​ is

310​

20

95​

none of these

p=5!6C3​⋅3!,q=6!⋅3! ⇒qp​=310​

Q. 5 boys and 3 girls sit in a line so that $p$ is the number of arrangements when no two girls sit together and $q$ is the number of arrangements when all the girls sit together, then $\frac{p}{q}$ is

$\frac{10}{3}$

$\frac{5}{9}$

$p = 5!^{6} C_{3} \cdot 3!, q = 6! \cdot 3!$
$\Rightarrow \frac{p}{q} = \frac{10}{3}$