Question

5.6 L of a gas at S.T.P. weighs equal to 8 g. The vapour density of gas is

• A. 32
• B. 16
• C. 8
• D. 40

Answer 1

Answer: (B)

Mass of $22\cdot 4L$ gas at $S.T.P$
$=\frac{8\times 22\cdot 4}{5\cdot 6}=32g$
Mol. mass $=32$
$\therefore V.D.=\frac{3}{2}\times \frac{1}{2}$
$=16$