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  4. 5.6 L of a gas at S.T.P. weighs equal to 8 g. The vapour density of gas is

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Q. 5.6 L of a gas at S.T.P. weighs equal to 8 g. The vapour density of gas is

Some Basic Concepts of Chemistry

Solution:

Mass of $22\cdot4\, L$ gas at $S.T.P$
$=\frac{8\times22\cdot4}{5\cdot6}=32\,g$
Mol. mass $=32$
$\therefore V.D. =\frac32 \times \frac{1}{2}$
$=16$