5.0 g of sodium hydroxide (molar mass 40 g mol-1) is dissolved in little quantity of water and the solution is diluted up to 100 ml. What is the molarity of the resulting solution ?

Question

5.0 g of sodium hydroxide (molar mass 40 g mol-1) is dissolved in little quantity of water and the solution is diluted up to 100 ml. What is the molarity of the resulting solution ? (A) 0.1 mol dm - 3 (B) 1.0 mol dm - 3 (C) 0.125 mol dm - 3 (D) 1.25 mol dm - 3

Tardigrade Admin · Accepted Answer

Given, W (mass of solute) =5.0 g m (molar mass of solute) =40 g mol -1 Volume =100 mL Molarity is given as, M =( text Moles of solute / text Volume of solution (in L) ) M =(W × 1000/m × text Volume of solution (in mL )) M =(5.0 g × 1000/40 × 100) =1.25 mol dm -3

Q. $5.0 g$ of sodium hydroxide (molar mass $40 g m o l^{- 1}$ ) is dissolved in little quantity of water and the solution is diluted up to $100 m l$ . What is the molarity of the resulting solution ?

$0.1 m o l d m^{- 3}$

$1.0 m o l d m^{- 3}$

$0.125 m o l d m^{- 3}$

$1.25 m o l d m^{- 3}$

Q. 5.0g of sodium hydroxide (molar mass 40gmol−1) is dissolved in little quantity of water and the solution is diluted up to 100ml. What is the molarity of the resulting solution ?

0.1moldm−3

1.0moldm−3

0.125moldm−3

1.25moldm−3

Given, W (mass of solute) =5.0g m (molar mass of solute) =40gmol−1 Volume =100mL Molarity is given as, M= Volume of solution (in L) Moles of solute ​ M=m× Volume of solution (in mL)W×1000​ M=40×1005.0g×1000​ =1.25moldm−3

Q. $5.0 g$ of sodium hydroxide (molar mass $40 g m o l^{- 1}$ ) is dissolved in little quantity of water and the solution is diluted up to $100 m l$ . What is the molarity of the resulting solution ?

$0.1 m o l d m^{- 3}$

$1.0 m o l d m^{- 3}$

$0.125 m o l d m^{- 3}$

$1.25 m o l d m^{- 3}$