40% (w/v) of NaCl solution (specific gravity = 1.12) is equivalent to

Question

40% (w/v) of NaCl solution (specific gravity = 1.12) is equivalent to (A) 3.57× 105 ppm (B) 3.57× 106 ppm (C) 1× 106 ppm (D) 4× 105 ppm

Tardigrade Admin · Accepted Answer

Volume of solution = 100 mL
Mass of solution

=

Volume

\times

density
Mass of solution

= 100 \times 1.12 = 112

g
Concentration in ppm

= \frac{W _{so l u t e}}{W _{so l u t i o n}} \times 1 0^{6}

ppm in NaCl solution

= \frac{40}{112} \times 1 0^{6}

= 3.57 \times 1 0^{5}

ppm.

Q. 40% (w/v) of NaCl solution (specific gravity = 1.12) is equivalent to