Question

40% (w/v) of NaCl solution (specific gravity = 1.12) is equivalent to

• A. $3.57\times 10^{5}$ ppm
• B. $3.57\times 10^{6}$ ppm
• C. $1\times 10^{6}$ ppm
• D. $4\times 10^{5}$ ppm

Answer 1

Answer: (A)

Volume of solution = 100 mL
Mass of solution $=$ Volume $\times $ density
Mass of solution $=100\times 1.12=112$ g
Concentration in ppm $=\frac{W_{s o l u t e}}{W_{s o l u t i o n}}\times 10^{6}$
ppm in NaCl solution $=\frac{40}{112}\times 10^{6}$
$=3.57\times 10^{5}$ ppm.