Question

$4L$ -atm is equal to

• A. $40.50cal$
• B. $78.75cal$
• C. $95.23cal$
• D. $96cal$

Answer 1

Answer: (D)

$\because 1L-atm=101.266J$

$\therefore 4L-atm=101.266\times 4J$

$=405.06J$

$=\frac{405.06}{4.2}cal$

$[\because 1cal=4.2J]$

$=96.4cal$