Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
4 g of hydrocarbon ( C x H y ) on complete combustion gave 12 g of CO 2 . What is the empirical formula of the hydrocarbon?
Q.
4
g
of hydrocarbon
(
C
x
H
y
)
on complete combustion gave
12
g
of
C
O
2
.
What is the empirical formula of the hydrocarbon?
2983
194
Organic Chemistry – Some Basic Principles and Techniques
Report Error
A
C
H
3
36%
B
C
4
H
9
11%
C
C
H
9%
D
C
3
H
8
45%
Solution:
Per cent of carbon in compound
44
12
×
weight of compound
weight of
C
O
2
×
100
44
12
×
4
12
×
100
=
81.81%
%
of
H
=
100
−
81.81
=
18.19%
Hence; empirical formula of the compound
=
C
3
H
8
