4 g equimolar mixture of NaOH and Na 2 CO 3 contains x g of NaOH and y g of Na 2 CO 3. The value of x is g.

Question

4 g equimolar mixture of NaOH and Na 2 CO 3 contains x g of NaOH and y g of Na 2 CO 3. The value of x is g. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Total mass =4 g NOW NaOH: 'a' mol W NaOH +W Na 2 CO 3=4 Na 2 CO 3 :'a' mol ⇒ 40 a+106 a=4 ⇒ a=(4/146) text mol ⇒ therefore mass of N a O H is: (4/146) × 40 g =1.095 ≈ 1

Q. $4 g$ equimolar mixture of $N a O H$ and $N a_{2} C O_{3}$ contains $xg$ of $N a O H$ and y $g$ of $N a_{2} C O_{3}$ . The value of $x$ is _______ $g$ .

Total mass $= 4 g$
NOW
$N a O H :^{'} a^{'}$ mol $W_{N a O H} + W_{N a_{2} C O_{3}} = 4$
$N a_{2} C O_{3} :^{'} a^{'}$ mol $\Rightarrow 40 a + 106 a = 4$
$\Rightarrow a = \frac{4}{146} mol$
$\Rightarrow$ therefore mass of $N a O H$ is
$: \frac{4}{146} \times 40 g$
$= 1.095 \approx 1$

Q. 4g equimolar mixture of NaOH and Na2​CO3​ contains xg of NaOH and y g of Na2​CO3​. The value of x is _______ g.

Total mass =4g NOW NaOH:′a′ mol WNaOH​+WNa2​CO3​​=4 Na2​CO3​:′a′ mol ⇒40a+106a=4 ⇒a=1464​ mol ⇒ therefore mass of NaOH is :1464​×40g =1.095≈1

Q. $4 g$ equimolar mixture of $N a O H$ and $N a_{2} C O_{3}$ contains $xg$ of $N a O H$ and y $g$ of $N a_{2} C O_{3}$ . The value of $x$ is _______ $g$ .

Total mass $= 4 g$
NOW
$N a O H :^{'} a^{'}$ mol $W_{N a O H} + W_{N a_{2} C O_{3}} = 4$
$N a_{2} C O_{3} :^{'} a^{'}$ mol $\Rightarrow 40 a + 106 a = 4$
$\Rightarrow a = \frac{4}{146} mol$
$\Rightarrow$ therefore mass of $N a O H$ is
$: \frac{4}{146} \times 40 g$
$= 1.095 \approx 1$