4-bromo-1-butanol [A] can be converted into 5-hydroxy pentanoic acid [B] by following method [s] I. A xrightarrowMg/ textether xrightarrow[(ii)H3O+](i) CO2 B II. A xrightarrowKCN xrightarrowH3O+ B III. A xrightarrowaq. KOH xrightarrow KMnO4/H+ B select the correct alternate.

Question

4-bromo-1-butanol [A] can be converted into 5-hydroxy pentanoic acid [B] by following method [s] I. A xrightarrowMg/ textether xrightarrow[(ii)H3O+](i) CO2 B II. A xrightarrowKCN xrightarrowH3O+ B III. A xrightarrowaq. KOH xrightarrow KMnO4/H+ B select the correct alternate. (A)  I, text II, text III  (B)  I, text II  (C)  II, text III  (D)  II

Tardigrade Admin · Accepted Answer

I. BrCH2CH2CH2CH2OH [A] xrightarrowMg/ textether Br oversets+Mg oversets-CH2CH2CH2CH2OH <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/08b0dfb5181251f2923de439e5216569-.png" /> III. BrCH2CH2CH2CH2OH xrightarrow[-KBr]Aq.KOHHOCH2CH2CH2CH2OH

Q. $4$ -bromo- $1$ -butanol $[A]$ can be converted into $5$ -hydroxy pentanoic acid [B] by following method $[s]$

I. $A M g / ether (i) C O_{2} (ii) H_{3} O^{+} B$
II. $A K CN H_{3} O^{+} B$
III. $A a q . K O H K M n O_{4} / H^{+} B$
select the correct alternate.

$I, II, III$

$I, II$

$II, III$

$II$

I. $B r C H_{2} C H_{2} C H_{2} C H_{2} O H [A] M g / ether B r M g s + C s - H_{2} C H_{2} C H_{2} C H_{2} O H$

III. $B r C H_{2} C H_{2} C H_{2} C H_{2} O H A q . K O H - K B r H OC H_{2} C H_{2} C H_{2} C H_{2} O H$

Q. 4-bromo-1-butanol [A] can be converted into 5-hydroxy pentanoic acid [B] by following method [s] I. AMg/ether​(i)CO2​(ii)H3​O+​B II. AKCN​H3​O+​B III. Aaq.KOH​KMnO4​/H+​B select the correct alternate.

I,II,III

I,II

II,III

II