4.5 moles each of hydrogen and iodine were heated in a sealed ten litre vessel. At equilibrium 3 moles of HI were found. The equilibrium constant for H2(g) +I2(g) is

Question

4.5 moles each of hydrogen and iodine were heated in a sealed ten litre vessel. At equilibrium 3 moles of HI were found. The equilibrium constant for H2(g) +I2(g) is (A) 1 (B) 10 (C) 5 (D) 0.33

Tardigrade Admin · Accepted Answer

2 moles of HI are formed from 1 mole of H2 and I2. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/e9f6c56182c1f38460b71b29da9bf454-.png" /> K=([Hi]2/[H2][I2])=((3)2/3×3)=1

Q. $4.5 m o l es$ each of hydrogen and iodine were heated in a sealed ten litre vessel. At equilibrium 3 moles of HI were found. The equilibrium constant for
$H_{2 (g)} + I_{2 (g)}$ is

$1$

$10$

$5$

$0.33$

$2 m o l es$ of $H I$ are formed from $1 m o l e$ of $H_{2}$ and $I_{2}$ .

$K = \frac{[ H i ] ^{2}}{[ H _{2} ] [ I _{2} ]} = \frac{( 3 ) ^{2}}{3 \times 3} = 1$

Q. 4.5moles each of hydrogen and iodine were heated in a sealed ten litre vessel. At equilibrium 3 moles of HI were found. The equilibrium constant for H2(g)​+I2(g)​ is

1

10

5

0.33

2moles of HI are formed from 1mole of H2​ and I2​. K=[H2​][I2​][Hi]2​=3×3(3)2​=1

Q. $4.5 m o l es$ each of hydrogen and iodine were heated in a sealed ten litre vessel. At equilibrium 3 moles of HI were found. The equilibrium constant for
$H_{2 (g)} + I_{2 (g)}$ is

$1$

$10$

$5$

$0.33$

$2 m o l es$ of $H I$ are formed from $1 m o l e$ of $H_{2}$ and $I_{2}$ .

$K = \frac{[ H i ] ^{2}}{[ H _{2} ] [ I _{2} ]} = \frac{( 3 ) ^{2}}{3 \times 3} = 1$