Q.
4.5 moles each of hydrogen and iodine heated in a sealed 10 litre vessel. At equilibrium, 3 moles of HI was found. The equilibrium constant for. H2(g)+I2(g)⇌2HI(g) is
Total mole at equilibrium =(1−α)+2α=1+α H2+I2⇌2HI
Initial cone. x4.5x4.52x0
From question 2x=3 x=23=1.5
So cone, at equilibrium 4.5−1.5 of H2 =4.5−1.5 of I2 and 3 of HI K=[I2][H2][HI]2=3×33×3=1