Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
4.0 g of NaOH is dissolved in 100 mL solution. The normality of the solution is
Q.
4.0
g
of
N
a
O
H
is dissolved in
100
m
L
solution. The normality of the solution is
4392
194
Manipal
Manipal 2010
Solutions
Report Error
A
0.1 N
19%
B
0.5 N
13%
C
4.0 N
21%
D
1.0 N
47%
Solution:
Normality
=
volume of solution in litre
gram equivalents of solute
Given, mass of solute
=
4
g
Molecular mass of
N
a
O
H
=
23
+
16
+
1
=
40
Volume of solution
=
100
m
L
=
100/1000
L
=
0.1
L
∴
Normality
=
0.1
4/40
=
1.0
N