4.0 g of caustic soda ( NaOH ) (mol mass 40 ) contains same number of sodium ions as are present in-

Question

4.0 g of caustic soda ( NaOH ) (mol mass 40 ) contains same number of sodium ions as are present in- (A) 10.6 g of Na 2 CO 3 (mol. mass .106) (B) 58.5 g of NaCl (Formula mass 58.5 ) (C) 100 ml of 0.5 M Na 2 SO 4 (Formula mass 142 ) (D) 1 mol of NaNO 3 (mol. mass .85)

Tardigrade Admin · Accepted Answer

(4/40) × N A =( N A /10) atom 0.5 M Na 2 SO 4 =(0.5 × 2/100) × N A =( N A /10)

Q. $4.0 g$ of caustic soda $(N a O H)$ (mol mass 40 ) contains same number of sodium ions as are present in-

$10.6 g$ of $N a_{2} C O_{3}$ (mol. mass $106)$

$58.5 g$ of $N a Cl$ (Formula mass 58.5 )

$100 m l$ of $0.5 MN a_{2} S O_{4}$ (Formula mass 142 )

$1 m o l$ of $N a N O_{3}$ (mol. mass $85)$

$\frac{4}{40} \times N_{A} = \frac{N _{A}}{10}$ atom

$0.5 M N a_{2} S O_{4}$

$= \frac{0.5 \times 2}{100} \times N_{A} = \frac{N _{A}}{10}$

Q. 4.0g of caustic soda (NaOH) (mol mass 40 ) contains same number of sodium ions as are present in-

10.6g of Na2​CO3​ (mol. mass 106)

58.5g of NaCl (Formula mass 58.5 )

100ml of 0.5MNa2​SO4​ (Formula mass 142 )

1mol of NaNO3​ (mol. mass 85)