34 g of hydrogen peroxide is present in 1120 ml of solution. This solution is called

Question

34 g of hydrogen peroxide is present in 1120 ml of solution. This solution is called (A) 10 volume solution (B) 20 volume (C) 30 volume (D) 32 volume

Tardigrade Admin · Accepted Answer

Amount of H2O2 in one ml = (34/1120) g H2O2 → H2O + (1/2) O2 ∵ 34 g of H2O gives 16 g or 11200 ml of O2 ∴ (34/1120) g H2O2 = (11200/34) × (34/1120) = 10 ml O2 ∴ Volume strength of H2O2 = 10 volume

Q. $34 g$ of hydrogen peroxide is present in $1120 m l$ of solution. This solution is called

$10$ volume solution

$20$ volume

$30$ volume

$32$ volume

Q. 34g of hydrogen peroxide is present in 1120ml of solution. This solution is called

10 volume solution

20 volume

30 volume

32 volume

Amount of H2​O2​ in one ml=112034​g H2​O2​→H2​O+21​O2​ ∵34g of H2​O gives 16 g or 11200ml of O2​ ∴112034​gH2​O2​=3411200​×112034​=10mlO2​ ∴ Volume strength of H2​O2​=10 volume

Q. $34 g$ of hydrogen peroxide is present in $1120 m l$ of solution. This solution is called

$10$ volume solution

$20$ volume

$30$ volume

$32$ volume