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  4. 34 g of hydrogen peroxide is present in 1120 ml of solution. This solution is called

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Q. $34 \,g$ of hydrogen peroxide is present in $1120\, ml$ of solution. This solution is called

Some Basic Concepts of Chemistry

Solution:

Amount of $H_2O_2$ in one $ml \,= \frac{34}{1120} g$
$H_2O_2 \to H_2O + \frac{1}{2} O_2$
$\because 34\,g$ of $H_2O$ gives $16$ g or $11200\, ml$ of $O_2$
$\therefore \frac{34}{1120} \,g \,H_2O_2 = \frac{11200}{34} \times \frac{34}{1120} = 10\,ml \,O_2$
$\therefore $ Volume strength of $H_2O_2 = 10$ volume