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Question
Chemistry
( 32 Ge 76, 34 Se 76) and ( 14 Si 30, 16 S 32) are the examples of-
Q.
(
32
G
e
76
,
34
S
e
76
)
and
(
14
S
i
30
,
16
S
32
)
are the examples of-
1849
213
Structure of Atom
Report Error
A
Isotopes and isobars
14%
B
Isobars and isotones
70%
C
Isotones and isotopes
7%
D
Isobars and isotopes
9%
Solution:
Number of neutrons
=
M
−
A
Number of neutrons in
14
S
i
30
=
30
−
14
=
16
Number of neutrons in
16
S
i
32
=
32
−
16
=
16
Because of the presence of same number of neutrons,
14
S
i
30
and
16
S
32
are called isotones.
Hence;
32
G
e
76
,
34
S
e
76
and
14
S
i
30
and
16
S
32
are isobars and isotones.