300 g of 25 % w / w solution of solute A is mixed with 400 g of 40 %( w / w ) solution of another solute B. What is the w/ w percentage of new mixture?

Question

300 g of 25 % w / w solution of solute A is mixed with 400 g of 40 %( w / w ) solution of another solute B. What is the w/ w percentage of new mixture? (A) 10.71% in A (B) 35% in B (C) 25% in A (D) 40% in B

Tardigrade Admin · Accepted Answer

A: 300 g of 25 % w / w B: 400 g of 40 % w / w w / w % of A =(25 % text of 300/300+400)=(75/700) × 100=10.71 % w / w % of B =(40 % text of 400/300+400) × 100=22.85 %

Q. $300 g$ of $25% w / w$ solution of solute $A$ is mixed with $400 g$ of $40% (w / w)$ solution of another solute $B$ . What is the w $/ w$ percentage of new mixture?

10.71% in A

35% in B

25% in A

40% in B

A: $300 g$ of $25% w / w$
$B : 400 g$ of $40% w / w$
$w / w %$ of $A = \frac{25% of 300}{300 + 400} = \frac{75}{700} \times 100 = 10.71%$
$w / w %$ of $B = \frac{40% of 400}{300 + 400} \times 100 = 22.85%$

Q. 300g of 25%w/w solution of solute A is mixed with 400g of 40%(w/w) solution of another solute B. What is the w/w percentage of new mixture?