3-Methylpent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is :

Question

3-Methylpent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is : (A) Two (B) Four (C) Six (D) Zero

Tardigrade Admin · Accepted Answer

Since product (X) contains two chiral centres and it is unsymmetrical. So, its total stereoisomers =22 = 4.

Q. $3$ -Methylpent- $2$ -ene on reaction with $H B r$ in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is :

Two

Four

Six

Zero

Since product (X) contains two chiral centres and it is unsymmetrical.

So, its total stereoisomers $= 2^{2} = 4.$

Q. 3-Methylpent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is :

Two

Four

Six

Zero

Since product (X) contains two chiral centres and it is unsymmetrical. So, its total stereoisomers =22=4.

Q. $3$ -Methylpent- $2$ -ene on reaction with $H B r$ in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is :

Since product (X) contains two chiral centres and it is unsymmetrical.

So, its total stereoisomers $= 2^{2} = 4.$