3 Indian and 3 American men and their wives are to be seated round a circular table. Let m denotes the number of ways when the Indian couples are together and n denotes the number of ways when all the six couples are together. If m = kn then k equals

Question

3 Indian and 3 American men and their wives are to be seated round a circular table. Let m denotes the number of ways when the Indian couples are together and n denotes the number of ways when all the six couples are together. If m = kn then k equals (A) 36 (B) 42 (C) 45 (D) 48

Tardigrade Admin · Accepted Answer

m = 8! 23

n =5 ! 26 ( m / n )=(8 ⋅ 7 ⋅ 6 ⋅ 5 ! ⋅ 23/5 ! ⋅ 26)

k =42

Q. 3 Indian and 3 American men and their wives are to be seated round a circular table. Let $m$ denotes the number of ways when the Indian couples are together and $n$ denotes the number of ways when all the six couples are together. If $m = kn$ then $k$ equals

36

42

45

48

$m = 8! 2^{3}$

$n = 5! 2^{6}$
$\frac{m}{n} = \frac{8 \cdot 7 \cdot 6 \cdot 5 ! \cdot 2 ^{3}}{5 ! \cdot 2 ^{6}}$

$k = 42$

Q. 3 Indian and 3 American men and their wives are to be seated round a circular table. Let m denotes the number of ways when the Indian couples are together and n denotes the number of ways when all the six couples are together. If m=kn then k equals

36

42

45

48

m=8!23 n=5!26 nm​=5!⋅268⋅7⋅6⋅5!⋅23​ k=42

Q. 3 Indian and 3 American men and their wives are to be seated round a circular table. Let $m$ denotes the number of ways when the Indian couples are together and $n$ denotes the number of ways when all the six couples are together. If $m = kn$ then $k$ equals

$m = 8! 2^{3}$

$n = 5! 2^{6}$
$\frac{m}{n} = \frac{8 \cdot 7 \cdot 6 \cdot 5 ! \cdot 2 ^{3}}{5 ! \cdot 2 ^{6}}$

$k = 42$