3 d-transition series of elements starts with Sc and ends with Zn. The electronic configuration of Sc and Zn are respectively.

Question

3 d-transition series of elements starts with Sc and ends with Zn. The electronic configuration of Sc and Zn are respectively. (A) [ Ar ] 3 d1 4 s1 and [Ar] 3 d10 4 s1 (B) [ Ar ] 3 d1 4 s2 and [ Ar ] 3 d10 4 s2 (C) [ Ar ] 3 d2 4 s1 and [ Ar ] 3 d9 4 s3 (D) [ Ar ] 3 d3 4 s2 and [ Ar ] 3 d8 4 s2

Tardigrade Admin · Accepted Answer

Before the 4 p-orbital is filled, filling-up of 3 d-orbitals becomes energetically favourable and we come across 3 d transition series of elements. This starts from scandium (Z=21) which has electronic configuration =[ Ar ] 3 d1 4 s2 and end at zinc (Z=30) with electronic configuration =[ Ar ] 3 d10, 4 s2

Q. $3 d$ -transition series of elements starts with $S c$ and ends with $Z n$ . The electronic configuration of $S c$ and $Z n$ are respectively.

$[A r] 3 d^{1} 4 s^{1}$ and [Ar] $3 d^{10} 4 s^{1}$

$[A r] 3 d^{1} 4 s^{2}$ and $[A r] 3 d^{10} 4 s^{2}$

$[A r] 3 d^{2} 4 s^{1}$ and $[A r] 3 d^{9} 4 s^{3}$

$[A r] 3 d^{3} 4 s^{2}$ and $[A r] 3 d^{8} 4 s^{2}$

Q. 3d-transition series of elements starts with Sc and ends with Zn. The electronic configuration of Sc and Zn are respectively.

[Ar]3d14s1 and [Ar] 3d104s1

[Ar]3d14s2 and [Ar]3d104s2

[Ar]3d24s1 and [Ar]3d94s3

[Ar]3d34s2 and [Ar]3d84s2

Before the 4p-orbital is filled, filling-up of 3d-orbitals becomes energetically favourable and we come across 3d transition series of elements. This starts from scandium (Z=21) which has electronic configuration =[Ar]3d14s2 and end at zinc (Z=30) with electronic configuration =[Ar]3d10,4s2

Q. $3 d$ -transition series of elements starts with $S c$ and ends with $Z n$ . The electronic configuration of $S c$ and $Z n$ are respectively.

$[A r] 3 d^{1} 4 s^{1}$ and [Ar] $3 d^{10} 4 s^{1}$

$[A r] 3 d^{1} 4 s^{2}$ and $[A r] 3 d^{10} 4 s^{2}$

$[A r] 3 d^{2} 4 s^{1}$ and $[A r] 3 d^{9} 4 s^{3}$

$[A r] 3 d^{3} 4 s^{2}$ and $[A r] 3 d^{8} 4 s^{2}$