29 electrons are removed from Zn-atom (Z=30) by certain means .The minimum energy needed to remove the 30th electron ,will be:

Question

29 electrons are removed from Zn-atom (Z=30) by certain means .The minimum energy needed to remove the 30th electron ,will be: (A) 12.24 keV, (B) 408keV (C) 0.45keV (D) 765keV

Tardigrade Admin · Accepted Answer

After removing 29 electrons,Zn atom will become Zn+29: ∴ E = 13.6 Z2 eV = 12,240 eV = 12.24KeV

Q. 29 electrons are removed from Zn-atom (Z=30) by certain means .The minimum energy needed to remove the 30th electron ,will be:

12.24 keV,

408keV

0.45keV

765keV

After removing 29 electrons,Zn atom will become $Z n^{+ 29}$ :
$∴$ E = 13.6 $Z^{2}$ eV = 12,240 eV = 12.24KeV

Q. 29 electrons are removed from Zn-atom (Z=30) by certain means .The minimum energy needed to remove the 30th electron ,will be:

12.24 keV,

408keV

0.45keV

765keV

After removing 29 electrons,Zn atom will become Zn+29 : ∴ E = 13.6 Z2 eV = 12,240 eV = 12.24KeV

After removing 29 electrons,Zn atom will become $Z n^{+ 29}$ :
$∴$ E = 13.6 $Z^{2}$ eV = 12,240 eV = 12.24KeV