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Physics
29 electrons are removed from Zn-atom (Z=30) by certain means .The minimum energy needed to remove the 30th electron ,will be:
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Q. 29 electrons are removed from Zn-atom (Z=30) by certain means .The minimum energy needed to remove the 30th electron ,will be:
Atoms
A
12.24 keV,
47%
B
408keV
18%
C
0.45keV
27%
D
765keV
8%
Solution:
After removing 29 electrons,Zn atom will become $Zn^{+29}$ :
$\therefore $ E = 13.6 $Z^2$ eV = 12,240 eV = 12.24KeV