25 mL of 3.0 M HCl are mixed with 75 mL of 4.0 M HCl . If the volumes are additive, the molarity of the final mixture will be

Question

25 mL of 3.0 M HCl are mixed with 75 mL of 4.0 M HCl . If the volumes are additive, the molarity of the final mixture will be (A) 4.0 M (B) 3.75 M (C) 4.25 M (D) 3.50 M

Tardigrade Admin · Accepted Answer

on mixing two solutions of same substance, Molarity of the final mixture, M=(M1V1+M2V2/V1+V2) =(25×3+75×4/25+75)=(375/100) =3.75 M

Q. $25 m L$ of $3.0 M$ $H Cl$ are mixed with $75 m L$ of $4.0 M H Cl$ . If the volumes are additive, the molarity of the final mixture will be

4.0 M

3.75 M

4.25 M

3.50 M

on mixing two solutions of same substance,
Molarity of the final mixture, $M = \frac{M _{1} V _{1} + M _{2} V _{2}}{V _{1} + V _{2}}$
$= \frac{25 \times 3 + 75 \times 4}{25 + 75} = \frac{375}{100}$
$= 3.75 M$

Q. 25mL of 3.0M HCl are mixed with 75mL of 4.0MHCl . If the volumes are additive, the molarity of the final mixture will be