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Q. $ 25\, mL $ of $ 3.0\, M $ $ HCl $ are mixed with $ 75 \,mL $ of $ 4.0 \,M\, HCl $ . If the volumes are additive, the molarity of the final mixture will be

AMUAMU 2014Solutions

Solution:

on mixing two solutions of same substance,
Molarity of the final mixture, $ M=\frac{M_{1}V_{1}+M_{2}V_{2}}{V_{1}+V_{2}}$
$=\frac{25\times3+75\times4}{25+75}=\frac{375}{100}$
$=3.75\,M$